- #1

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## Homework Statement

Marian, who is standing on her balcony, is surprised by a pigeon and throws a flowerpot up in the air at 2.1m/s. It takes 3.0 seconds for the flowerpot to smash to the ground. The flowerpot experiences acceleration due to gravity of 9.81m/s^2 [down].

a) how high is Marian's balcony?

b) How fast was the flowerpot moving just before it smashed to the ground?

## Homework Equations

Delta d = V1(delta t) + 1/2(a)(delta t^2)

Delta d = V2(delta t) - 1/2(a)(delta t^2)

V2 ^2 = V1^2+2(a)(delta d)

## The Attempt at a Solution

a) part really confused me. I applied the first equation to find the distance:

d = 2.1m/s(3.0 seconds) +1/2(-9.81m/s^2 [down])(3.0^2)

d = 6.3 - 44.145

Now, unless she lives underground then I am clearly doing something wrong. If I were to apply the second equation, I would get a positive value but that only applies when there is a velocity final. This question has me completely stumped, I would like it if answerers could guide me through it by giving hints and not giving me the full answer.

For b part, I know that all I would need to apply is the third equation after finding the distance. But since the question states

**just before**, would I use 2.9 as my change in time instead of 3.0 seconds which is when the pot hit the ground?

Thanks in advance for all the help.